MinT - Information on Result #1974214

Information on Result #1974214

There is no OA(16ⁿ⁺¹⁰¹, s, S₁₆, 101) with finite t and arbitrarily large s, because strength reduction would yield OA(16ⁿ⁺², s, S₁₆, 2) with finite t and arbitrarily large s, but

lower bound on the number of runs for OAs with strength kÂ =Â 2 and arbitrarily large number of factors s [i]

Mode: Bound.

Optimality

Show details for fixed k and s.

Other Results with Identical Parameters

None.

Depending Results

None.