Information on Result #2156584
There is no linear OA(2113, 124, F2, 57) (dual of [124, 11, 58]-code), because 1 times truncation would yield linear OA(2112, 123, F2, 56) (dual of [123, 11, 57]-code), but
- residual code [i] would yield linear OA(256, 66, F2, 28) (dual of [66, 10, 29]-code), but
- adding a parity check bit [i] would yield linear OA(257, 67, F2, 29) (dual of [67, 10, 30]-code), but
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Compare with Markus Grassl’s online database of code parameters.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OA(2227, 239, F2, 114) (dual of [239, 12, 115]-code) | [i] | Residual Code | |