Information on Result #2156654
There is no linear OA(2123, 133, F2, 63) (dual of [133, 10, 64]-code), because 1 times truncation would yield linear OA(2122, 132, F2, 62) (dual of [132, 10, 63]-code), but
- residual code [i] would yield linear OA(260, 69, F2, 31) (dual of [69, 9, 32]-code), but
- “BGV†bound on codes from Brouwer’s database [i]
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Compare with Markus Grassl’s online database of code parameters.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OA(2249, 260, F2, 126) (dual of [260, 11, 127]-code) | [i] | Residual Code | |