Information on Result #2156703
There is no linear OA(2128, 137, F2, 65) (dual of [137, 9, 66]-code), because 1 times truncation would yield linear OA(2127, 136, F2, 64) (dual of [136, 9, 65]-code), but
- residual code [i] would yield linear OA(263, 71, F2, 32) (dual of [71, 8, 33]-code), but
- residual code [i] would yield linear OA(231, 38, F2, 16) (dual of [38, 7, 17]-code), but
- residual code [i] would yield linear OA(215, 21, F2, 8) (dual of [21, 6, 9]-code), but
- residual code [i] would yield linear OA(27, 12, F2, 4) (dual of [12, 5, 5]-code), but
- residual code [i] would yield linear OA(215, 21, F2, 8) (dual of [21, 6, 9]-code), but
- residual code [i] would yield linear OA(231, 38, F2, 16) (dual of [38, 7, 17]-code), but
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Compare with Markus Grassl’s online database of code parameters.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OA(2258, 268, F2, 130) (dual of [268, 10, 131]-code) | [i] | Residual Code | |