Information on Result #2164536
There is no linear OA(4199, 214, F4, 149) (dual of [214, 15, 150]-code), because 1 times truncation would yield linear OA(4198, 213, F4, 148) (dual of [213, 15, 149]-code), but
- construction Y1 [i] would yield
- linear OA(4197, 205, F4, 148) (dual of [205, 8, 149]-code), but
- construction Y1 [i] would yield
- linear OA(4196, 201, F4, 148) (dual of [201, 5, 149]-code), but
- residual code [i] would yield linear OA(448, 52, F4, 37) (dual of [52, 4, 38]-code), but
- 1 times truncation [i] would yield linear OA(447, 51, F4, 36) (dual of [51, 4, 37]-code), but
- residual code [i] would yield linear OA(448, 52, F4, 37) (dual of [52, 4, 38]-code), but
- OA(48, 205, S4, 4), but
- discarding factors would yield OA(48, 121, S4, 4), but
- the Rao or (dual) Hamming bound shows that M ≥ 65704 > 48 [i]
- discarding factors would yield OA(48, 121, S4, 4), but
- linear OA(4196, 201, F4, 148) (dual of [201, 5, 149]-code), but
- construction Y1 [i] would yield
- OA(415, 213, S4, 8), but
- discarding factors would yield OA(415, 135, S4, 8), but
- the Rao or (dual) Hamming bound shows that M ≥ 1082 768311 > 415 [i]
- discarding factors would yield OA(415, 135, S4, 8), but
- linear OA(4197, 205, F4, 148) (dual of [205, 8, 149]-code), but
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Compare with Markus Grassl’s online database of code parameters.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
Result | This result only | Method | ||
---|---|---|---|---|
1 | No linear OA(4200, 230, F4, 149) (dual of [230, 30, 150]-code) | [i] | Construction Y1 (Bound) |