Information on Result #551665
There is no linear OOA(2126, 123, F2, 2, 70) (dual of [(123, 2), 120, 71]-NRT-code), because 14 step m-reduction would yield linear OA(2112, 123, F2, 56) (dual of [123, 11, 57]-code), but
- residual code [i] would yield linear OA(256, 66, F2, 28) (dual of [66, 10, 29]-code), but
- adding a parity check bit [i] would yield linear OA(257, 67, F2, 29) (dual of [67, 10, 30]-code), but
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OOA(2126, 123, F2, 3, 70) (dual of [(123, 3), 243, 71]-NRT-code) | [i] | Depth Reduction | |
| 2 | No linear OOA(2126, 123, F2, 4, 70) (dual of [(123, 4), 366, 71]-NRT-code) | [i] | ||
| 3 | No linear OOA(2126, 123, F2, 5, 70) (dual of [(123, 5), 489, 71]-NRT-code) | [i] | ||
| 4 | No linear OOA(2126, 123, F2, 6, 70) (dual of [(123, 6), 612, 71]-NRT-code) | [i] | ||