Information on Result #552611
There is no linear OOA(2168, 166, F2, 2, 90) (dual of [(166, 2), 164, 91]-NRT-code), because 10 step m-reduction would yield linear OA(2158, 166, F2, 80) (dual of [166, 8, 81]-code), but
- residual code [i] would yield linear OA(278, 85, F2, 40) (dual of [85, 7, 41]-code), but
- “Hel†bound on codes from Brouwer’s database [i]
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OOA(2168, 166, F2, 3, 90) (dual of [(166, 3), 330, 91]-NRT-code) | [i] | Depth Reduction | |
| 2 | No linear OOA(2168, 166, F2, 4, 90) (dual of [(166, 4), 496, 91]-NRT-code) | [i] | ||
| 3 | No linear OOA(2168, 166, F2, 5, 90) (dual of [(166, 5), 662, 91]-NRT-code) | [i] | ||
| 4 | No linear OOA(2168, 166, F2, 6, 90) (dual of [(166, 6), 828, 91]-NRT-code) | [i] | ||
| 5 | No linear OOA(2168, 166, F2, 7, 90) (dual of [(166, 7), 994, 91]-NRT-code) | [i] | ||
| 6 | No linear OOA(2168, 166, F2, 8, 90) (dual of [(166, 8), 1160, 91]-NRT-code) | [i] | ||