Information on Result #555254
There is no linear OOA(2260, 266, F2, 2, 132) (dual of [(266, 2), 272, 133]-NRT-code), because 4 step m-reduction would yield linear OA(2256, 266, F2, 128) (dual of [266, 10, 129]-code), but
- residual code [i] would yield linear OA(2128, 137, F2, 64) (dual of [137, 9, 65]-code), but
- residual code [i] would yield linear OA(264, 72, F2, 32) (dual of [72, 8, 33]-code), but
- adding a parity check bit [i] would yield linear OA(265, 73, F2, 33) (dual of [73, 8, 34]-code), but
- “BJV†bound on codes from Brouwer’s database [i]
- adding a parity check bit [i] would yield linear OA(265, 73, F2, 33) (dual of [73, 8, 34]-code), but
- residual code [i] would yield linear OA(264, 72, F2, 32) (dual of [72, 8, 33]-code), but
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OOA(2260, 266, F2, 3, 132) (dual of [(266, 3), 538, 133]-NRT-code) | [i] | Depth Reduction | |
| 2 | No linear OOA(2260, 266, F2, 4, 132) (dual of [(266, 4), 804, 133]-NRT-code) | [i] | ||
| 3 | No linear OOA(2260, 266, F2, 5, 132) (dual of [(266, 5), 1070, 133]-NRT-code) | [i] | ||
| 4 | No linear OOA(2260, 266, F2, 6, 132) (dual of [(266, 6), 1336, 133]-NRT-code) | [i] | ||
| 5 | No linear OOA(2260, 266, F2, 7, 132) (dual of [(266, 7), 1602, 133]-NRT-code) | [i] | ||
| 6 | No linear OOA(2260, 266, F2, 8, 132) (dual of [(266, 8), 1868, 133]-NRT-code) | [i] | ||