Information on Result #1856178

There is no (8, m, 15)-net in base 2 for arbitrarily large m, because m-reduction would yield (8, 40, 15)-net in base 2, but

Mode: Bound.

Optimality

Show details for fixed m and s, m and t, t and s.

Other Results with Identical Parameters

None.

Depending Results

The following results depend on this result:

ResultThis
result
only
Method
1No (8, 14)-sequence in base 2 [i]Net from Sequence
2No (8, 8+k, 15)-net in base 2 for arbitrarily large k [i]Logical Equivalence (for Nets with Unbounded m)
3No (8, m, 15)-net in base 2 with unbounded m [i]
4No digital (8, 8+k, 15)-net over F2 for arbitrarily large k [i]
5No digital (8, m, 15)-net over F2 with unbounded m [i]