Best Known (4, 4+10, s)-Nets in Base 3

(4, 4+10, 12)-Net over F3Constructive and digital

Digital (4, 14, 12)-net over F3, using

(4, 4+10, 18)-Net over F3 — Upper bound on s (digital)

There is no digital (4, 14, 19)-net over F3, because

(4, 4+10, 23)-Net in Base 3 — Upper bound on s

There is no (4, 14, 24)-net in base 3, because

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