Information on Result #2156598
There is no linear OA(2114, 128, F2, 57) (dual of [128, 14, 58]-code), because 1 times truncation would yield linear OA(2113, 127, F2, 56) (dual of [127, 14, 57]-code), but
- residual code [i] would yield linear OA(257, 70, F2, 28) (dual of [70, 13, 29]-code), but
- adding a parity check bit [i] would yield linear OA(258, 71, F2, 29) (dual of [71, 13, 30]-code), but
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Compare with Markus Grassl’s online database of code parameters.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OA(2228, 243, F2, 114) (dual of [243, 15, 115]-code) | [i] | Residual Code | |