Information on Result #551229
There is no linear OOA(298, 102, F2, 2, 52) (dual of [(102, 2), 106, 53]-NRT-code), because 4 step m-reduction would yield linear OA(294, 102, F2, 48) (dual of [102, 8, 49]-code), but
- residual code [i] would yield linear OA(246, 53, F2, 24) (dual of [53, 7, 25]-code), but
- 1 times code embedding in larger space [i] would yield linear OA(247, 54, F2, 24) (dual of [54, 7, 25]-code), but
- adding a parity check bit [i] would yield linear OA(248, 55, F2, 25) (dual of [55, 7, 26]-code), but
- “vT4†bound on codes from Brouwer’s database [i]
- adding a parity check bit [i] would yield linear OA(248, 55, F2, 25) (dual of [55, 7, 26]-code), but
- 1 times code embedding in larger space [i] would yield linear OA(247, 54, F2, 24) (dual of [54, 7, 25]-code), but
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OOA(298, 102, F2, 3, 52) (dual of [(102, 3), 208, 53]-NRT-code) | [i] | Depth Reduction | |
| 2 | No linear OOA(298, 102, F2, 4, 52) (dual of [(102, 4), 310, 53]-NRT-code) | [i] | ||
| 3 | No linear OOA(298, 102, F2, 5, 52) (dual of [(102, 5), 412, 53]-NRT-code) | [i] | ||
| 4 | No linear OOA(298, 102, F2, 6, 52) (dual of [(102, 6), 514, 53]-NRT-code) | [i] | ||
| 5 | No linear OOA(298, 102, F2, 7, 52) (dual of [(102, 7), 616, 53]-NRT-code) | [i] | ||
| 6 | No linear OOA(298, 102, F2, 8, 52) (dual of [(102, 8), 718, 53]-NRT-code) | [i] | ||