Information on Result #552107
There is no linear OOA(2148, 142, F2, 2, 82) (dual of [(142, 2), 136, 83]-NRT-code), because 14 step m-reduction would yield linear OA(2134, 142, F2, 68) (dual of [142, 8, 69]-code), but
- residual code [i] would yield linear OA(266, 73, F2, 34) (dual of [73, 7, 35]-code), but
- “Hel†bound on codes from Brouwer’s database [i]
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OOA(2148, 142, F2, 3, 82) (dual of [(142, 3), 278, 83]-NRT-code) | [i] | Depth Reduction | |
| 2 | No linear OOA(2148, 142, F2, 4, 82) (dual of [(142, 4), 420, 83]-NRT-code) | [i] | ||
| 3 | No linear OOA(2148, 142, F2, 5, 82) (dual of [(142, 5), 562, 83]-NRT-code) | [i] | ||
| 4 | No linear OOA(2148, 142, F2, 6, 82) (dual of [(142, 6), 704, 83]-NRT-code) | [i] | ||
| 5 | No linear OOA(2148, 142, F2, 7, 82) (dual of [(142, 7), 846, 83]-NRT-code) | [i] | ||
| 6 | No linear OOA(2148, 142, F2, 8, 82) (dual of [(142, 8), 988, 83]-NRT-code) | [i] | ||