Information on Result #552154
There is no linear OOA(2150, 142, F2, 2, 84) (dual of [(142, 2), 134, 85]-NRT-code), because 16 step m-reduction would yield linear OA(2134, 142, F2, 68) (dual of [142, 8, 69]-code), but
- residual code [i] would yield linear OA(266, 73, F2, 34) (dual of [73, 7, 35]-code), but
- “Hel†bound on codes from Brouwer’s database [i]
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OOA(2150, 142, F2, 3, 84) (dual of [(142, 3), 276, 85]-NRT-code) | [i] | Depth Reduction | |
| 2 | No linear OOA(2150, 142, F2, 4, 84) (dual of [(142, 4), 418, 85]-NRT-code) | [i] | ||