Information on Result #555050
There is no linear OOA(2254, 250, F2, 2, 135) (dual of [(250, 2), 246, 136]-NRT-code), because 15 step m-reduction would yield linear OA(2239, 250, F2, 120) (dual of [250, 11, 121]-code), but
- residual code [i] would yield linear OA(2119, 129, F2, 60) (dual of [129, 10, 61]-code), but
- residual code [i] would yield linear OA(259, 68, F2, 30) (dual of [68, 9, 31]-code), but
- adding a parity check bit [i] would yield linear OA(260, 69, F2, 31) (dual of [69, 9, 32]-code), but
- “BGV†bound on codes from Brouwer’s database [i]
- adding a parity check bit [i] would yield linear OA(260, 69, F2, 31) (dual of [69, 9, 32]-code), but
- residual code [i] would yield linear OA(259, 68, F2, 30) (dual of [68, 9, 31]-code), but
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OOA(2254, 250, F2, 3, 135) (dual of [(250, 3), 496, 136]-NRT-code) | [i] | Depth Reduction | |
| 2 | No linear OOA(2254, 250, F2, 4, 135) (dual of [(250, 4), 746, 136]-NRT-code) | [i] | ||
| 3 | No linear OOA(2254, 250, F2, 5, 135) (dual of [(250, 5), 996, 136]-NRT-code) | [i] | ||
| 4 | No linear OOA(2254, 250, F2, 6, 135) (dual of [(250, 6), 1246, 136]-NRT-code) | [i] | ||
| 5 | No linear OOA(2254, 250, F2, 7, 135) (dual of [(250, 7), 1496, 136]-NRT-code) | [i] | ||
| 6 | No linear OOA(2254, 250, F2, 8, 135) (dual of [(250, 8), 1746, 136]-NRT-code) | [i] | ||