Information on Result #556041
There is no linear OOA(3110, 101, F3, 2, 79) (dual of [(101, 2), 92, 80]-NRT-code), because 16 step m-reduction would yield linear OA(394, 101, F3, 63) (dual of [101, 7, 64]-code), but
- residual code [i] would yield linear OA(331, 37, F3, 21) (dual of [37, 6, 22]-code), but
- “Bou†bound on codes from Brouwer’s database [i]
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OOA(3110, 101, F3, 3, 79) (dual of [(101, 3), 193, 80]-NRT-code) | [i] | Depth Reduction | |
| 2 | No linear OOA(3110, 101, F3, 4, 79) (dual of [(101, 4), 294, 80]-NRT-code) | [i] | ||
| 3 | No linear OOA(3110, 101, F3, 5, 79) (dual of [(101, 5), 395, 80]-NRT-code) | [i] | ||