Information on Result #561413
There is no linear OOA(4238, 241, F4, 2, 180) (dual of [(241, 2), 244, 181]-NRT-code), because 4 step m-reduction would yield linear OA(4234, 241, F4, 176) (dual of [241, 7, 177]-code), but
- residual code [i] would yield linear OA(458, 64, F4, 44) (dual of [64, 6, 45]-code), but
- residual code [i] would yield linear OA(414, 19, F4, 11) (dual of [19, 5, 12]-code), but
- 1 times truncation [i] would yield linear OA(413, 18, F4, 10) (dual of [18, 5, 11]-code), but
- “Liz†bound on codes from Brouwer’s database [i]
- 1 times truncation [i] would yield linear OA(413, 18, F4, 10) (dual of [18, 5, 11]-code), but
- residual code [i] would yield linear OA(414, 19, F4, 11) (dual of [19, 5, 12]-code), but
Mode: Bound (linear).
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
| Result | This result only | Method | ||
|---|---|---|---|---|
| 1 | No linear OOA(4238, 241, F4, 3, 180) (dual of [(241, 3), 485, 181]-NRT-code) | [i] | Depth Reduction | |