Information on Result #1013202
Linear OOA(569, 5224, F5, 3, 13) (dual of [(5224, 3), 15603, 14]-NRT-code), using (u, u+v)-construction based on
- linear OOA(58, 14, F5, 3, 6) (dual of [(14, 3), 34, 7]-NRT-code), using
- extracting embedded OOA [i] based on digital (2, 8, 14)-net over F5, using
- linear OOA(561, 5210, F5, 3, 13) (dual of [(5210, 3), 15569, 14]-NRT-code), using
- OOA 3-folding [i] based on linear OA(561, 15630, F5, 13) (dual of [15630, 15569, 14]-code), using
- discarding factors / shortening the dual code based on linear OA(561, 15631, F5, 13) (dual of [15631, 15570, 14]-code), using
- construction X applied to Ce(12) ⊂ Ce(11) [i] based on
- linear OA(561, 15625, F5, 13) (dual of [15625, 15564, 14]-code), using an extension Ce(12) of the primitive narrow-sense BCH-code C(I) with length 15624 = 56−1, defining interval I = [1,12], and designed minimum distance d ≥ |I|+1 = 13 [i]
- linear OA(555, 15625, F5, 12) (dual of [15625, 15570, 13]-code), using an extension Ce(11) of the primitive narrow-sense BCH-code C(I) with length 15624 = 56−1, defining interval I = [1,11], and designed minimum distance d ≥ |I|+1 = 12 [i]
- linear OA(50, 6, F5, 0) (dual of [6, 6, 1]-code), using
- discarding factors / shortening the dual code based on linear OA(50, s, F5, 0) (dual of [s, s, 1]-code) for arbitrarily large s, using
- construction X applied to Ce(12) ⊂ Ce(11) [i] based on
- discarding factors / shortening the dual code based on linear OA(561, 15631, F5, 13) (dual of [15631, 15570, 14]-code), using
- OOA 3-folding [i] based on linear OA(561, 15630, F5, 13) (dual of [15630, 15569, 14]-code), using
Mode: Constructive and linear.
Optimality
Show details for fixed k and m, n and k, k and s, k and t, n and m, m and s, m and t, n and s, n and t.
Other Results with Identical Parameters
None.
Depending Results
The following results depend on this result:
Result | This result only | Method | ||
---|---|---|---|---|
1 | Linear OOA(569, 2611, F5, 15, 13) (dual of [(2611, 15), 39096, 14]-NRT-code) | [i] | OOA Folding and Stacking with Additional Row |