Information on Result #1857114

There is no (2, 15)-sequence in base 5, because net from sequence would yield (2, m, 16)-net in base 5 for arbitrarily large m, but

Mode: Bound.

Optimality

Show details for fixed m and s, m and t, t and s.

Other Results with Identical Parameters

None.

Depending Results

The following results depend on this result:

ResultThis
result
only
Method
1No (2, 15)-sequence in base 5 (for arbitrarily large k) [i]Logical Equivalence (for Sequences)
2No (2, m, 15)-net in base 5 with m > ∞ [i]
3No digital (2, 15)-sequence over F5 (for arbitrarily large k) [i]
4No digital (2, m, 15)-net over F5 with m > ∞ [i]