Information on Result #1858400

There is no (1, 130)-sequence in base 64, because net from sequence would yield (1, m, 131)-net in base 64 for arbitrarily large m, but

Mode: Bound.

Optimality

Show details for fixed m and s, m and t, t and s.

Other Results with Identical Parameters

None.

Depending Results

The following results depend on this result:

ResultThis
result
only
Method
1No (1, 130)-sequence in base 64 (for arbitrarily large k) [i]Logical Equivalence (for Sequences)
2No (1, m, 130)-net in base 64 with m > ∞ [i]
3No digital (1, 130)-sequence over F64 (for arbitrarily large k) [i]
4No digital (1, m, 130)-net over F64 with m > ∞ [i]