Information on Result #1869814

There is no (2, 2+k, 16)-net in base 5 for arbitrarily large k, because logical equivalence would yield (2, m, 16)-net in base 5 for arbitrarily large m, but

Mode: Bound.

Optimality

Show details for fixed k and s, k and t, t and s.

Other Results with Identical Parameters

None.

Depending Results

None.