Best Known (2, 6, s)-Nets in Base 3

(2, 6, 14)-Net over F3Constructive and digital

Digital (2, 6, 14)-net over F3, using

(2, 6, 14)-Net over F3 — Upper bound on s (digital)

There is no digital (2, 6, 15)-net over F3, because

(2, 6, 17)-Net in Base 3 — Upper bound on s

There is no (2, 6, 18)-net in base 3, because

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