Best Known (56−45, 56, s)-Nets in Base 5
(56−45, 56, 32)-Net over F5 — Constructive and digital
Digital (11, 56, 32)-net over F5, using
- net from sequence [i] based on digital (11, 31)-sequence over F5, using
- Niederreiter–Xing sequence construction II/III [i] based on function field F/F5 with g(F) = 11 and N(F) ≥ 32, using
(56−45, 56, 64)-Net over F5 — Upper bound on s (digital)
There is no digital (11, 56, 65)-net over F5, because
- extracting embedded orthogonal array [i] would yield linear OA(556, 65, F5, 45) (dual of [65, 9, 46]-code), but
- construction Y1 [i] would yield
- linear OA(555, 59, F5, 45) (dual of [59, 4, 46]-code), but
- residual code [i] would yield linear OA(510, 13, F5, 9) (dual of [13, 3, 10]-code), but
- 1 times truncation [i] would yield linear OA(59, 12, F5, 8) (dual of [12, 3, 9]-code), but
- residual code [i] would yield linear OA(510, 13, F5, 9) (dual of [13, 3, 10]-code), but
- OA(59, 65, S5, 6), but
- discarding factors would yield OA(59, 58, S5, 6), but
- the Rao or (dual) Hamming bound shows that M ≥ 2 001465 > 59 [i]
- discarding factors would yield OA(59, 58, S5, 6), but
- linear OA(555, 59, F5, 45) (dual of [59, 4, 46]-code), but
- construction Y1 [i] would yield
(56−45, 56, 65)-Net in Base 5 — Upper bound on s
There is no (11, 56, 66)-net in base 5, because
- 1 times m-reduction [i] would yield (11, 55, 66)-net in base 5, but
- extracting embedded orthogonal array [i] would yield OA(555, 66, S5, 44), but
- the linear programming bound shows that M ≥ 975608 482889 356309 897266 328334 808349 609375 / 3111 > 555 [i]
- extracting embedded orthogonal array [i] would yield OA(555, 66, S5, 44), but